Use

Verilog code to compute the unsigned function f = 5A + 2B without directly using the multiplication operator in Verilog. Assume that: * The input arguments A and B are 8-bit unsigned numbers *The output SUM is a 12-bit number Use a similar technique from the code bellow| module adder4 (carrying, X, Y, S, carryout); input carrying; input [3:0] X, Y; output [3:0] S; output carryout; wire [3:1] C; full add stage 0 (carrying, X[0], Y[0], S[0], C[l]); full add stage (C[l], XJ1], Y[l], S[l], C[2]); full add stage2 (C[2], XJ2], Y[2], S[2], C[3]); full add stage3 (C[3], X[3], Y[3], S[3], carryout); end module Verilog code to compute the unsigned function f = 5A + 2B without directly using the multiplication operator in Verilog. Assume that: * The input arguments A and B are 8-bit unsigned numbers *The output SUM is a 12-bit number Use a similar technique from the code bellow| module adder4 (carrying, X, Y, S, carryout); input carrying; input [3:0] X, Y; output [3:0] S; output carryout; wire [3:1] C; full add stage 0 (carrying, X[0], Y[0], S[0], C[l]); full add stage (C[l], XJ1], Y[l], S[l], C[2]); full add stage2 (C[2], XJ2], Y[2], S[2], C[3]); full add stage3 (C[3], X[3], Y[3], S[3], carryout); end module