Question: Used digital multi-meter to read capacitance. No capacitor can be over 10uF. Information from the readings is below: C1 (F) = 30x10^(-12) C2(F) =

 

Used digital multi-meter to read capacitance. No capacitor can be over 10uF.Information from the readings is below: C1 (F) = 30x10^(-12) C2(F) =

Used digital multi-meter to read capacitance. No capacitor can be over 10uF. Information from the readings is below: C1 (F) = 30x10^(-12) C2(F) = 30x10^(-12) C3(F) = 30x10^(-12) For question 1a, 2a, and 3a the Measured capacitance has already been found: 1a.) Calculate total capacitance of series combination and show work. Also measure capacitance series combination with multi-meter. Compare values by computing percent difference. Series Capacitance (Calculated) = ? (Find this and show work) Series Capacitance (Measured) = 12x10^(-12) 1b.) Percent Difference = ? (Show and find answer) 2a.) Calculate total capacitance for parallel combination show work. Measured capacitance parallel combination with multi-meter. Compare values by computing percent difference. Parallel Capacitance (Calculated) = ? (Find this and show work) Parallel Capacitance (Measured) = 94x10^(-12) 2b.) Percent Difference = ? (Show and find answer) 3a.) Calculate total capacitance of parallel/series combination and show work. Also measure capacitance parallel/series combination with multi-meter. Compare values by computing percent difference. Parallel/Series Capacitance (Calculated) = ? (Find this and show work) Parallel/Series Capacitance (Measured) = 51x10^(-12) 3b.) Percent Difference = ? (Show and find answer) Using series and parallel combinations of capacitance compute the equivalent capacitance for the circuit shown below. Number UF 5.15 UF 3.55 UF HE 6.25 F 1.25 UF To. 0.750 UF 15.0 F

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