// Used for onput & output stream

#include

// Used for round() function

#include

using namespace std;

// Main function

int main()

{

// Variables used to store coordinates of start and end points

int x0, y0, x1, y1;

// Take coordinates of start point

cout

cin >> x0 >> y0;

// Take coordinates of end point

cout

cin >> x1 >> y1;

// Find dx & dy

int dx = x1 - x0;

int dy = y1 - y0;

// Find number of steps required for generating pixels

int steps = abs(dx) > abs(dy) ? abs(dx) : abs(dy);

// Find the increment in x & y for each steps

float Xinc = dx / (float) steps;

float Yinc = dy / (float) steps;

// Varibale store each coordinates of line

float x = x0;

float y = y0;

// Print the table header

cout

// Loop to find the coordinates of line

for (int i = 0; i

{

// Print points

cout

cout

// increment in x

x += Xinc;

// increment in y

y += Yinc;

}

return 0;

}

The above code is written in dda format. I want the same, but in midpoint format, to solve the problem in the image

Midpoint Line Drawing Algorithm Example-1: Draw line A(4, 8) and B(10, 12) using midpoint line drawing algorithm Solution: - Here starting point is (4.8) and ending point is (10, 12). We have = dx = X2 - Xi = dy = Y2 - Y = 10 - 4 = 12 - 8 = 6 = 4 = m = dy dx = 4/6 = 0.67 ::m 0 As do > 0, NE is chosen and the next pixel to be plotted will be Y+ 1) = (5,9) SCREENCAST MATIC