Question: using c++ 28. Look at the following function definition: void getNumberlint &n) cout > n In this function, the parameter n is a reference variable.
using c++
28. Look at the following function definition: void getNumberlint &n) cout > n In this function, the parameter n is a reference variable. Rewrite the function so n is a pointer
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
