Question: using C++ finish and alter the code, to sort the anagram to which is to be ordered by their count (meaning the highest number of

using C++ finish and alter the code, to sort the anagram to which is to be ordered by their count (meaning the highest number of the alphabets in each letter/character is to be outputted/printed first) You may alter (add/remove/alter the part of the code) where it says 'code here'

#include

#include

using namespace std;

#define SIZE 25

string sortChar(string str)

{

int i, key, j;

int n = str.length();

//for (i = 0; i

for (i = 0; i

for (j = 0; j

/* CODE HERE */

if(str[j] > str[j+1]) {

key = str[j];

str[j] = str[j+1];

str[j+1] = key;

}

}

}

return str;

}

void sortString(string strArray[])

{

int i, j;

for (i = 0; i

/* CODE HERE */

string temp;

for (j = 0; j

/* CODE HERE */

}

}

}

void printStringArray(string strArray[])

{

for (int i = 0; i

cout

}

}

int main()

{

string strArray[] = {"alert", "cares", "cautioned", "marine","acres",

"slaw", "education", "dear", "airmen", "awls",

"asp", "auctioned", "ear", "later", "fairy tales",

"races", "laws", "pas", "remain", "sap",

"are", "dare", "read", "alter", "rail safety"};

cout > "

printStringArray(strArray);

cout

sortString(strArray);

cout > "

printStringArray(strArray);

cout

return 0;

}

using C++ finish and alter the code, to sort the anagram to

What output should look like - Check the link in the comment

#include #include 1 4using namespace std; 6 7 8 #define SIZE 25 string sortChar (string str) int i, key, j; int n- str.length); 12 13 14 for (i0; i>" > " ?? endl; printStringArray (strArray); cout

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!