Question: Using complex numbers, show that sin7 u = 1 64 (35 sin u 21 sin 3u + 7 sin 5u sin 7u). Find the modulus
Using complex numbers, show that sin7 u = 1 64 (35 sin u 21 sin 3u + 7 sin 5u sin 7u). Find the modulus and argument of ( ) ( ) ( ) ( ) 3 4 12 5 3 4 12 5 4 2 2 3 + + j j j j.
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
