Using complex numbers, show that sin7 u = 1 64 (35 sin u 21 sin 3u +
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Using complex numbers, show that sin7 u = 1 64 (35 sin u 21 sin 3u + 7 sin 5u sin 7u). Find the modulus and argument of ( ) ( ) ( ) ( ) 3 4 12 5 3 4 12 5 4 2 2 3 + + j j j j.
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Income Tax Fundamentals 2013
ISBN: 9781285586618
31st Edition
Authors: Gerald E. Whittenburg, Martha Altus Buller, Steven L Gill
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