Using lab7 with tow-day lead time (all original values)

Time left 0:06:38 Hide Using lab 7 with a three-day lead time (all original values), we will analyze six different scenarios to determine which would be the best scenario based on the total cost. Scenario A - Min is 3,500 and Max is 5,500. All other values remain the same as lab 7 original values. The total cost would be |$246,492 Scenario B - Min is 3,500 and Max is 6,000. All other values remain the same as lab 7 original values. The total cost would be $307,893 Scenario C - Min is 4,000 and Max is 5,500. All other values remain the same as lab 7 original values. The total cost would be |$424,627 Scenario D - Min is 4,000 and Max is 6,000. All other values remain the same as lab 7 original values. The total cost would be $259,530 Scenario E - Min is 4,500 and Max is 5,500. All other values remain the same as lab 7 original values. The total cost would be | $290,521 Scenario F - Min is 4,500 and Max is 6,000. All other values remain the same as lab 7 original values. The total cost would be | $301,993 Based on the above scenarios, we know that scenario ( C| would cost us the most, therefore we wouldn't want to use those min and max values. On the flip side, scenario A yields us the best combination of min and max resulting in the least cost. $259,530 $424,627 $301,993 $290,521 $246,492 $307,893 D F E A B tv DII DD 20 O G K F8 F9 F4 F5 F6 F7 F3