Question: USING MATLAB The quadratic equation ax2+bx+c=0 normally has two roots. If a = 0 x = -c/b If b2 = 4ac x1 = x2 =

USING MATLAB

The quadratic equation ax2+bx+c=0 normally has two roots.

If a = 0

x = -c/b

If b2 = 4ac

x1 = x2 = -b/(2a);

Otherwise

x1 = [-b+sqrt(b2-4ac)]/(2a), x2 = [-b-sqrt(b2-4ac)]/(2a);

Determine the roots corresponding to each set:

(1) a = 2, b = 4, c = 1

(2) a = 4, b = 2, c = 3

(3) a = 2, b = 4, c = 2

(4) a = 0, b = 3, c = 2

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