Question: Using MySQL, create the following queries using the following tables...animal , volunteer, adopter List the name, weight, and breed id of each animal in the
Using MySQL, create the following queries using the following tables...animal , volunteer, adopter
List the name, weight, and breed id of each animal in the database and only show animals between 2 different weights. Have the user input those 2 weights.
Create a query that will return the volunteer id followed by the volunteer's first and last name with their initial letters shown and the rest redacted in separate columns. For example, John Doe should display as J*** D**. Show only the people from cities that start with the letter G. Order by their last name.
Create a report that displays the id, animal (animal name and sex concatenated with a comma and space in between), age, and arrival date for all animals. Prompt user for a low and high age which is order by animal's age.
Create a report that display the id, animal name, age('*' that represents each year), and arrival date which is ordered by arrival date between Jan 17 and the present.
Display the name (concatenate the name and age) as name and age with a coma, arrival as arrival, and months there and also do not have a volunteer. Order by days there descending.
Display the adopters full name and street address and prompt user to enter the name of the city where the adopter is from and order by the last name.
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