Question: Using Newton's Method to solve 5x - cos(x)=0, with an inital approximation of x_0=-4, the value of x^3( to 4 decimal places in: -0.63940.19670.26890.1962

Using Newton's Method to solve 5x - cos(x)=0, with an inital approximation of x_0=-4, the value of x^3( to 4 decimal places in: -0.63940.19670.26890.1962

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