Question: Using Pumping lemma, prove that the {0^n 1^n 2^n | n greaterthanorequalto 0} language over the alphabet {a, b} is not a regular language

Using Pumping lemma, prove that the {0^n 1^n 2^n | n greaterthanorequalto 0} language over the alphabet {a, b} is not a regular language
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