Question: Using python 3, Thanks! Note: The number in this list (thresholds1]) represents how many people get involved in 12 months respectively. 1st: >>> test_alert(thresholds[1], [0,0,4])
Using python 3, Thanks!![Using python 3, Thanks! Note: The number in this list "(thresholds1])" represents](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/09/66f3d69ec05d6_22266f3d69e38a9a.jpg)
Note:
The number in this list "(thresholds1])" represents how many people get involved in 12 months respectively.
1st:
>>> test_alert(thresholds[1], [0,0,4]) -1
Because 0,0 or 0,4 not exceed 0,1.5 or 1.5,11.6 continuously , so return -1
2nd:
>>> test_alert(thresholds[1], [0,10,23,30]) 'MAR'
Becasuse 10,23 exceed 1.5 ,11.6 continuously so return MAY( Because 23 means may)
3rd:
>>> test_alert(thresholds[1], [0,10,23,30], num_months=3) -1
Since num_month = 3, we need consider 3 month together.
Also, 0,10,23 and 10,23,30 did not exceed 0.0, 1.5,11.6 and 1.5,11.6,34.4 continusly , so return -1
Write a function test_alert(thresholds , counts, num_months=2) that takes as input a list of monthly thresholds, a list of monthly case counts for the year to date, and an optional parameter that specifies the number of consecutive months that the threshold must be exceeded before an alert is triggered. Thresholds refers to the output from calculate_alert_levels (aligned_counts ). The function should return the month that the alert is triggered, if the threshold has be exceeded for num_months, or -1 if no alert has been triggered so far. Assumptions You can assume that the length of counts is always less than the length of thresholds. >>> print (thresholds [1]) [0.0, 1.5, 11.6, 34.4, 89.6, 139.2, 81.6, 73.2, 29.4, 11.7, 0.0, 0.0] >>> test_alert(thresholds [1], [0,0,4]) >>> test_alert(thresholds [1], [0, 10, 23,30]) MAR >>> test_alert(thresholds [1], [0, 10,23,301, num_months=3) >>> test_alert(thresholds [1], [10, 1,5,45,93]) MAY
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