USING PYTHON CODE PLEASE

We are making n stone piles! The first pile has n stones. If n is even, then all succeeding piles will have an even number of stones. If n is odd, all succeeding piles will have an odd number of stones. Each pile must be more stones than the previous pile but as few as possible. Write a Python function to find and display the number of stones in each pile. The function should accept 1 argument that represents the initial number of stones in pile 1 and the number of piles to be generated.

Example Input 1

Enter number of piles: 8

Example Output 1

Number of stones in each pile:

Pile 1 - 8

Pile 2 - 10

Pile 3 - 12

Pile 4 - 14

Pile 5 - 16

Pile 6 - 18

Pile 7 - 20

Pile 8 - 22

Example Input 2

Enter number of piles: 7

Example Output 2

Number of stones in each pile:

Pile 1 - 7

Pile 2 - 9

Pile 3 - 11

Pile 4 - 13

Pile 5 - 15

Pile 6 - 17

Pile 7 - 19