Using Python create a code that will decrypt a mono-alphabetic substitution cipher. The code must not require a key and must have the option to ignore spaces.

This is what I have so far:

import string

def decrypt_cipher(ciphertext, ignore_spaces=True):

# Create a frequency dictionary of the letters in the English alphabet

freq_dict = {'a': 8.167, 'b': 1.492, 'c': 2.782, 'd': 4.253, 'e': 12.702, 'f': 2.228,

'g': 2.015, 'h': 6.094, 'i': 6.966, 'j': 0.153, 'k': 0.772, 'l': 4.025,

'm': 2.406, 'n': 6.749, 'o': 7.507, 'p': 1.929, 'q': 0.095, 'r': 5.987,

's': 6.327, 't': 9.056, 'u': 2.758, 'v': 0.978, 'w': 2.360, 'x': 0.150,

'y': 1.974, 'z': 0.074}

# Create a dictionary to store the decryption mapping

decryption_map = {}

# Remove spaces from the ciphertext if the ignore_spaces flag is set

if ignore_spaces:

ciphertext = ciphertext.replace(" ", "")

# Count the frequency of each letter in the ciphertext

ciphertext_freq = {c: ciphertext.count(c) for c in string.ascii_lowercase}

# Sort the letters in the ciphertext by frequency

sorted_ciphertext_freq = sorted(ciphertext_freq, key=ciphertext_freq.get, reverse=True)

# Sort the letters in the English alphabet by frequency

sorted_english_freq = sorted(freq_dict, key=freq_dict.get, reverse=True)

# Create the decryption mapping

for i in range(len(sorted_ciphertext_freq)):

decryption_map[sorted_ciphertext_freq[i]] = sorted_english_freq[i]

# Decrypt the ciphertext using the decryption mapping

decrypted_text = ""

for c in ciphertext:

if c in decryption_map:

decrypted_text += decryption_map[c]

else:

decrypted_text += c

return decrypted_text

I need it to ask for user input of the encrypted text then output the decrypted plain text.