Question: using relational algebra branch ( branch _ name, branch _ city, assets ) customer ( ID , customer _ name, customer _ street, customer _

using relational algebra
branch(branch_name, branch_city, assets)
customer (ID, customer_name, customer_street, customer_city)
loan (loan_number, branch_name, amount)
borrower (ID, loan_number)
account (account_number, branch_name, balance)
depositor (ID, account_number)
Find loan-numbers with a loan amount greater than $10000.
Find the name of each branch located in "Chicago".
Find customers (depositor-ids) who have account with a balance greater than $6000.
Find the ID of each depositor who has an account with a balance greater than $6000 at the "Uptown"
or "Downtown" branch.
Find customer-ids who are both - 'depositors as well as borrowers'
Find customers who borrowed more money than they have in their account
Find the customers who have an account in the city that they live in.
Find which cities have at least one branch having at least one loan amount of more than $100000.
 using relational algebra branch(branch_name, branch_city, assets) customer (ID, customer_name, customer_street, customer_city)

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