Question: Using the attached SPSS data file... Sphericity Violated Data.sav Download Sphericity Violated Data.sav 1 st Run the Repeated Measure ANOVA in SPSS and look over
Using the attached SPSS data file...
Sphericity Violated Data.savDownload Sphericity Violated Data.sav
1stRun the Repeated Measure ANOVA in SPSS and look over the results for Mauchly'sWtest (Table 1 below)
1a. If the Sig. value for the Approx . Chi-Square test is greater than (>) .05, then the assumption of Sphericity has been met. See 2a.
1b. If the Sig. value for the Approx . Chi-Square test is less than (<) .05, then the assumption of Sphericity has been violated. See 2b, 3, 3a, 3b.
2a If the assumption of Sphericity had been met, you can interpret the F-ratio for the line Sphericity Assumed (see table 2)
2b If the assumption of Sphericity had been violated then interpret the F-ratio for the Greenhouse-Geisser adjustment or the Huynh-Feldt Adjustment. (See table 2). Here's how to decide which.
- Assuming that Sphericity had been violated (the Chi-square test for Mauchly's W is significant) examine Epsilon values in Table 1.
3a. IfW is significant and the Huynh-Feldt .75, then interpret the F-ratio for the Huynh-Feldt adjustment in Table 2. (Note Huynh is pronounced Win).
3b. IfWis significant and the Greenhouse-Geisser < .75, then interpret the F-ratio for the Greenhouse-Geisser adjustment in Table 2.
- Therefore, in the example below:
A preliminary analysis employing Mauchly's test indicated that the assumption of sphericity had violated (W= .312, 2(2) = 11.65,p= .003,Greenhouse-Geisser < .622).Therefore, as recommended by Field (2018), theGreenhouse-Geisser adjusted F-test was employed. The results for the test indicated that the three sample means do not differ significantly (F(1.185, 13.033) = 3.75,p= .070, 2 = .254). The Null Hypothesis (M1 = M2 = M3) is accepted).
(Note that if I were to interpret the F-test for the Sphericity Assumed findings, I would have concluded that the sample means do differ significantly (F)2, 22) = 3.75, p = .04). The Null Hypothesis is rejected. Rather the Alternative Hypotheses (M1 M2 M3) is supported by the analysis.
Table 1
Mauchly's Test of Sphericitya | |||||||
Measure: MEASURE_1 | |||||||
Within | Mauchly's | Approx | df | Sig. | Epsilonb | ||
Subjects | W | Chi-Sq. | Greenhouse | Huynh- | Lower- | ||
Effect | -Geisser | Feldt | bound | ||||
Time | 0.312 | 11.649 | 2 | 0.003 | 0.592 | 0.622 | 0.5 |
Tests the null hypothesis that the error covariance matrix of the orthonormalized transformed dependent variables is proportional to an identity matrix. | |||||||
a. Design: Intercept | |||||||
Within Subjects Design: Time | |||||||
b. May be used to adjust the degrees of freedom for the averaged tests of significance. Corrected tests are displayed in the Tests of Within-Subjects Effects table. |
Table 2.
| Tests of Within-Subjects Effects | |||||||
| Source | Type III SS | df | MS | F | p | p2 | |
| Time | Sphericity Assumed | 956.22 | 2 | 478.11 | 3.75 | 0.04 | 0.254 |
| Greenhouse-Geisser | 956.22 | 1.185 | 807.07 | 3.75 | 0.07 | 0.254 | |
| Huynh-Feldt | 956.22 | 1.245 | 768.19 | 3.75 | 0.067 | 0.254 | |
| Lower-bound | 956.22 | 1 | 956.22 | 3.75 | 0.079 | 0.254 | |
| Error(Time) | Sphericity Assumed | 2806.44 | 22 | 127.57 | |||
| Greenhouse-Geisser | 2806.44 | 13.033 | 215.34 | ||||
| Huynh-Feldt | 2806.44 | 13.693 | 204.96 | ||||
| Lower-bound | 2806.44 | 11 | 255.13 |
Reference.
Field, A. (2018). Discovering Statistics Using SPSS (5thedition). London: Sage
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
