Using the binomial expansion prove the following relations n (1+2) = (2) , xk, k k=0...

 

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Using the binomial expansion prove the following relations n (1+2)² = (2) ²², xk, k k=0 n n n (6)-(2) + (0) - () 0 4 6 (71) − (3) + (3) - (27) - 5 +... +... - 22/2 COS $(TT), 4 2n/2 sin(). 4 where in each case the sum includes terms up to (m) satisfying m <n. Check your results by computing both sides of both equations in the case n = 5. Using the binomial expansion prove the following relations n (1+2)² = (2) ²², xk, k k=0 n n (6)-(2) + (-6) (1)-(² 0 4 (71) − (3) + (3) - (27) - 5 +... +... - 22/2 COS $(TT), 4 2n/2 sin(). 4 where in each case the sum includes terms up to (m) satisfying m <n. Check your results by computing both sides of both equations in the case n = 5. Using the binomial expansion prove the following relations n (1+2)² = (2) ²², xk, k k=0 n n n (6)-(2) + (0) - () 0 4 6 (71) − (3) + (3) - (27) - 5 +... +... - 22/2 COS $(TT), 4 2n/2 sin(). 4 where in each case the sum includes terms up to (m) satisfying m <n. Check your results by computing both sides of both equations in the case n = 5. Using the binomial expansion prove the following relations n (1+2)² = (2) ²², xk, k k=0 n n (6)-(2) + (-6) (1)-(² 0 4 (71) − (3) + (3) - (27) - 5 +... +... - 22/2 COS $(TT), 4 2n/2 sin(). 4 where in each case the sum includes terms up to (m) satisfying m <n. Check your results by computing both sides of both equations in the case n = 5.