Using the celsius$\_$to$\_$kelvin function as a guide, create a new function, changing the name to kelvin$\_$to$\_$celsius, and modifying the function accordingly.

Sample output with input: $283\mathrm{.}15$

$10\mathrm{.}0$ C is $283\mathrm{.}15$ K

$283\mathrm{.}15$ K is $10\mathrm{.}0$ C def celsius$\_$to$\_$kelvin$($value$\_$celsius$)$:

value$\_$kelvin $=0\mathrm{.}0$

value$\_$kelvin $=$ value$\_$celsius $+273\mathrm{.}15$

return value$\_$kelvin

$\text{'}\text{'}\text{'}$ Your solution goes here $\text{'}\text{'}\text{'}$

value$\_$c $=10\mathrm{.}0$

print$($f$\text{'}\{$value$\_$c$\}$ C is $\{$celsius$\_$to$\_$kelvin$($value$\_$c$)\}$ K$\text{'})$

value$\_$k $=$ float$($input$())$

print$($f$\text{'}\{$value$\_$k$\}$ K is $\{$kelvin$\_$to$\_$celsius$($value$\_$k$)\}$ C$\text{'})$