Using the equations below and the titration results, what are the Kn of the EDTA-Copper complex? Show calculations.

Titration Results -> Titration of 0.01282M CuSO4 complete at 4.00 mL

Used: Cu(II) = 0.1023g mix with H2O = 50ml

Titrated 20ml of EDTA with peak at 4ml (color change to blue)

M + L = ML

where, K1 = [ML]/[M][L]

(Here, L in the denominator, supposed to be the alpha value)

MLn-1 + L = MLn

Kn = [ML4]/[ML3][L]

and the free energy for dissociation reaction is:

G = -RTLnKn .

where R= gas constant and T = temperature (in Kelvin).

The EDTA, a multi-dentate ligand forms complexes with metals of the form:

Mn+ + Y4- = MYn-4

K = [MYn-4]/[Mn+][Yn-4]

where Y4- is the EDTA ligand.