Question: Using the equations H (g) + F (g) 2 HF (g) H = -79.2 kJ/mol C (s) + 2 F (g) CF (g) H =

Using the equations H (g) + F (g) 2 HF (g) H = -79.2 kJ/mol C (s) + 2 F (g) CF (g) H = 141.3 kJ/mol 2 C(s) + 2 H (g) CH (g) H = -97.6 kJ/mol Determine the molar enthalpy (in kJ/mol) for the reaction CH (g) + 6 F (g) 2 CF (g) + 4 HF (g).

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