Question: Using the following code segment (in C++): proc (int x, int y) { x=x+y; y=x+y; cout <
Using the following code segment (in C++):
proc (int x, int y) {
x=x+y;
y=x+y;
cout< } main() { int y=2, x=3; proc (x,y); cout< proc (x,x); cout< Show output by call by reference.
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