Question: Using the following code segment (in C++): proc (int x, int y) { x=x+y; y=x+y; cout <

Using the following code segment (in C++):

proc (int x, int y) {

x=x+y;

y=x+y;

cout<

}

main() {

int y=2, x=3;

proc (x,y);

cout<

proc (x,x);

cout<

Show output by call by reference.

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