Using the half-reaction method, are the equations listed below the correct way to balance the following equation? Sn subscript 2 to the power of plus open parentheses aq close parentheses plus Cu subscript 2 to the power of plus open parentheses aq close parentheses rightwards arrow Sn subscript 4 to the power of plus open parentheses aq close parentheses plus Cu to the power of plus open parentheses aq close parentheses The reduction half-cell reaction would be: Cu to the power of plus 2 end exponent plus 2 straight e to the power of minus rightwards arrow Cu The oxidation half-cell reaction would be: Sn squared rightwards arrow Sn to the power of plus 2 end exponent plus 2 straight e to the power of minus The final equation would be: 2 Cu to the power of plus 2 end exponent plus Sn to the power of plus 2 end exponent rightwards arrow Sn to the power of plus 4 end exponent plus 2 Cu to the power of plus True False