Using the hash function h$($i$)=(3$i $+7)$ mod $11$

to hash the keys: $12,33,21,58,42,51,22,63,120,99,44$

we get: $10,7,4,5,1,6,7,9,4,7,7$

What is the contents of an $11$ element array $($elements $0-10)$ that results using these keys in this order and this function, assuming collisions are handled by linear probing?

$($The symbol $->$ denotes a reference to a list.$)$

a$.$

$->42,->21,->120,->58,->51,->33,->22,->99,->44,->63,->12$

b$.$

$120,42,99,44,21,58,51,33,22,63,12$

c$.$

$12,33,21,58,42,51,22,63,120,99,44$

d$.$

null, $->42,$ null, null, $->21->120,->58,->51,->33->22->99->44,$ null, $->63,->12$