Question: Using the method of substitution, I = Sz (2 + 3x)dz = [f(u)du where u = du = f(u) == Using the above information:

Using the method of substitution, I = Sz (2 + 3x)dz = [f(u)du where u = du = f(u) == Using the above information: z (2+3x)dz = [ f(u)du dx (in terms of u) (in terms of x) Note: Don't forget the constant of integration in the last two blanks.

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