Using the same data as question 3. State the lower boundary of the 95% prediction interval for the value of}; for a particular child with elevated lead levels. Anova Doe. who is 10 YEARS old. In your calculation use 32 = 5.22 no matter what you got for se in your calculation in question 6 and state your answer rounded to one place of decimal. Note that this is a twotailed interval= but you are entering only the lower boundary as your answer. You are asked for the lower boundary only in this question and the next because onQ wants ONE answer only and cannot handle both ends of an interval. If you were 95% condent that y falls. say, between 12.2 and 18.6. then the lower boundary of your interval would be 12.2. [Many people have had difficulty nding the yOhat value needed for this solution. For the Casio fx991ES PLUS C calculator: with the regression data already entered: press AC, input your x0 value then shift and 1: and enter 5 for the menu choice Reg, then 5 again for the menu choice y-hal and finally =.]