Using the subset this time using the Y86 assembly language we have seen so far, a) Write the assembly language lines that would perform the C++ line of code: a[10] = x[10] + y[10]. Assume the following information: i. The base address for a is currently stored in the register %edi, x is stored at %esi, and the address for y is %edx. ii. Use the register %eax to store the value of a[10], %ebx to store the value for x[10] and %ecx to store the value for y[10]. iii.Use immediate for any constants. b) Rewrite the C code for each of the steps that the compiler takes to convert this piece of code and then write the assembly: for (i=0; i