Question: Using the table showing partial pressures for the formation of ammonia and corresponding equilibrium constants, show that at 101 bar, apparent equilibrium constants equals 0.0072

Using the table showing partial pressures for the formation of ammonia and corresponding equilibrium constants, show that at 101 bar, apparent equilibrium constants equals 0.0072 and the thermodynamic equilibrium constant equals 0.0064.

Using the table showing partial pressures for the formation of ammonia and

Table 9.1 Equilibrium Constants for the Reaction N2(g) + H2(8)=NH3(g) at 450C Total pressure/bar PNH PN , K, K(KPK) 2.30 7.67 0.0064 0.0064 0.204 1.76 6.68 21.9 0.0066 10.2 30.3 50.6 101.0 302.8 10.7 4.65 16.6 108 326 35.2 65.0 152 223 19.4 0.994 0.975 0.95 0.89 0.70 0.50 0.0068 0.0072 0.0088 0.0130 0.0064 0.0065 0.0064 0.0062 42.8 606 56.5 0.0065

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