Using the tower geometry and gravity and wind loads, compute the

area of wrought iron necessary in each of the two idealized legs at

the second platform to give an efficiency of $1\mathrm{.}0,$ assuming that

$f_{\text{a}\text{l}\text{l}\text{o}\text{w}\text{a}\text{b}\text{l}\text{e}}=15$ksi. At the second platform: $x=380$ feet.