Question: Using this data provided calculate the efficiency: - Time ( seconds ) : - 0 1 2 0 2 4 0 3 0 0 3

Using this data provided calculate the efficiency:- Time (seconds):-
0
120
240
300
360
420
480
540
600
660
720
780
840
900
960
1020
1080
1140
1200
1260
1320
1380
1440
1500
1560
1620
1680
1740
1800
1860
1920
1980
2040
2100
2160
2220
2280
2340
2400
2460
2520
2580
2640
2700
2760
2820
2880
2940
3000
3060
3120
3180
3240
3300
3360
3420
3480
3540
3600
3660
3720
3780
3840
3900
3960
4020
4080
4140
4200
4260
4320
4380
4440
4500
4560
4620
4680
4740
4800
4860
4920
4980
5040
5100
5160
5220
5280
5340
5400 and for the data of temprature in celesius :-
27
28
29.4
30.3
30.7
31.5
32.1
32.7
33.2
33.8
34.3
34.8
35.1
35.4
35.8
36.3
36.9
37.3
37.8
38.4
38.9
39.4
39.8
40.3
40.7
41.1
41.5
42
42.4
42.8
43.2
43.6
44
44.4
44.8
45.3
45.6
45.9
46.4
46.8
47.2
47.5
48
48.5
48.9
49.4
49.8
50.2
50.7
51.2
51.6
52.1
52.7
53.1
53.6
54
54.4
55
55.2
55.6
56.1
56.5
56.9
57.2
57.6
57.9
58.3
58.6
59.1
59.4
59.8
60.2
60.6
60.8
61.1
61.6
62
62.2
62.5
62.9
63.3
63.8
64.1
64.5
64.9
65.2
65.7
66.2
66.5 The mass of water is 2650 mL ,and the irradiance is 1020 W/m^2, and the height of the tube is 1.65 m, and the inner tube circle is 0.044 m, and the outer tube circle diameter is 0.0508 m, using the specific heat of water is 4.18 J/g\deg C.

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