Question: (v2 - 2xy + 6x)dx - (x2 - 2xy + 2)dy =0 . (cos 2y - 3x y )dx + (cos 2y - 2x sin

(v2 - 2xy + 6x)dx - (x2 - 2xy + 2)dy

(v2 - 2xy + 6x)dx - (x2 - 2xy + 2)dy =0 . (cos 2y - 3x y )dx + (cos 2y - 2x sin 2y -2x y)dy = 0 . (w3+ wz? - z)dw + (23 + waz - w)dz = 0 2x[3x + y - y exp (-x?)]dx + [x2 + 3y2 + exp (-x2)]dy = 0 . (xy' + x - 2y +3)dx + x2ydy = 2(x + 1)dy: when x = 1,y = 1

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