Question: Variability 5. Compute the deviations from the mean. (A) -6, -2, +2, +6 (B) 6, 2, 2, 6 (C) -6, -3, +3, +6 (D)

Variability 5. Compute the deviations from the mean. (A) -6, -2, +2,

Variability 5. Compute the deviations from the mean. (A) -6, -2, +2, +6 (B) 6, 2, 2, 6 (C) -6, -3, +3, +6 (D) 6, 3, 3, 6 (E) -6, 0, 0, +6 6. Compute the distances to the mean, that is, the absolute deviations. (A) -6, -2, +2, +6 (B) 6, 2, 2, 6 (C) -6, -3, +3, +6 (D) 6, 3, 3, 6 (E) -6, 0, 0, +6 7. Compute the Mean Absolute Deviation. (A) 0 (B) 2 (C) 4 (D) 6 (E) 8 cm. 8. Compute the squared deviations. (A) 36, 4, 4, 36 (B) 6, 2, 2, 6 (C) -6, -3, +3, +6 (D) 6, 3, 3, 6 (E) -6, 0, 0, +6 9. Compute the Sum of Squared Deviations from the Mean. (A) 20 (B) 40 (C) 60 (D) 80 (E) 100 10. From this, compute the variance. (A) 26 2/3 (B) 0 (C) 40 (D) 60 (E) 80 1 Mean of a Discrete Distribution Consider the distribution p = = 1/2, p2 = 0, P3 = 0, p4 = 1/2 on the values 1, 2, 3, 4. 11. Compute the mean , as follows: Let Vi = : 1, v2 = 2, v3 = 3, v = 4. Then the mean is the probability-weighted average of the values, that is, = P1v1 + P2V2 + P3V3 + P4V4 = Mean = ? (A) 1.5 (B) 2.0 (C) 2.5 (D) 3.0 (E) 3.5

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