Question: variable. b . Keeping the restrictions in mind, solve the equation. 4 x + 3 + 2 x - 5 = 1 6 ( x

variable. b. Keeping the restrictions in mind, solve the equation.
4x+3+2x-5=16(x+3)(x-5)
a. What is/are the value or values of the variable that make(s) the denominators zero?
x=
(Simplify your answer. Use a comma to separate answers as needed.)
variable. b. Keeping the restrictions in mind, solve the equation. 4x+3+2x-5=16(x+3)(x-5)

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