Question: Vc(t) /Vmax = _6.32V/9.98V = 0.6333 Comment: theoretical value is Vc = Vmax(1-1/e) = 9.98V(1-1/2.71828) = 6.309V Vc/Vmax = 6.309V/9.98V = 0.6322, which is very

Vc(t) /Vmax = _6.32V/9.98V = 0.6333 Comment: theoretical value is Vc

Vc(t) /Vmax = _6.32V/9.98V = 0.6333 Comment: theoretical value is Vc = Vmax(1-1/e) = 9.98V(1-1/2.71828) = 6.309V Vc/Vmax = 6.309V/9.98V = 0.6322, which is very close to 0.6333 from the measured data. As we know, after one time constant, the voltage change is 63%, from 0 to 63%

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