vec$(F)(x,y)=($:$4x^3,4y^2$:$).$ Find a function $f(x,y)$ such that vec$(F)=$gradf. $f(x,y)=$

Evaluate ${\displaystyle \underset{n}{\overset{\phantom{}}{}}}$vec$(F)*dvec(r),$ where $C$ is the line segment from $(0,0)$ to $(6,6)$ followed by the segment from $(6,6)$ to $(7,3)$

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