Verify that X(t) is a fundamental matrix for the given system and compute x 1 (t). Then use the result that if X(t) is a fundamental matrix for the system x' = Ax, then x(t) = x(t)x 1 (0)x is the solution to the in alue problem x' = Ax, x(0) = x0- 060 -2 -2t #-0-338 x' 101 X, 1 1 x(0) = 5 24e6e -42-21 6e3t -20e-t 2e-2t 3e3t 060 a) If X(t) = [ (t) x2(t) x3 (t)] and A = 10 1 1 1 0 www validate the following identities and write the column vector that equals each side of the equation. x = Ax = x2=Ax2= X3-Ax3 b) Next, compute the Wronskian of X(t). W[x (1) X2 (1)x(1)]= Since the Wronskian is never and each column of X(t) is a solution to x' = Ax, X(t) is a fundamental matrix.