Question: Verify that y 1 ( t ) = 1 and y 2 ( t ) = t 1 2 are solutions of the differential equation

Verify that y1(t)=1 and y2(t)=t12 are solutions of the differential equation
y''+(y')2=0, for t>0
Then show that y=c1+c2t12 is not, in general, a solution of this equation. Explain why this result does not contradict Theorem 3.2.2 we learned in class.
Verify that y 1 ( t ) = 1 and y 2 ( t ) = t 1 2

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