Very simple question: Where does the lone pair on the ring go$?$

I understand that the hydroxyl group attacks the carbonyl carbon$($s$)[$I am aware that it breaks both bonds to make OH bonds on either end$]$; however, I do not know where the lone pair of electrons that form the bond to nitrogen go$.$ Do they just $***$ off or do they go to the nitrogen or what? Please help me understand. I thumbs up as soon as I can if the answer helps me$.$