Vo=gE A stone is dropped from rest from a height of 44.0 m. A second stone is thrown vertically downward from the same height 1.00 s after the first stone is dropped. The stones strike the ground at the same time. What is the initial speed of the second stone? Ax=vot - 1/2 (9.8) (+) - / (9.8) (+) = (g(t-11) (t-1)- - (9.8) (t-1) t = 7m (A) 33.7 m/s B) 12.2 m/s C) 23.7 m/s m D) 19.6 m/s E) 29.4 m/s Vo=0 t=t 72 t=t-1 29.36~29.4