Question: Vs = 2 0 V R 1 = 4 0 R _ 1 = 4 0 , OmegaR 1 = 4 0 R

Vs=20V
R1=40R_1=40\,\OmegaR1=40
R2=90R_2=90\,\OmegaR2=90
R3=90R_3=90\,\OmegaR3=90
Which KCL equation correctly describes the relationship between nodal voltage VaV_aVa and source voltage VsV_sVs?
Then, solve the equation for VaV_aVa.
(a)(R1R2R3)Va=VsR1(R_1- R_2- R_3)\times V_a =\frac{V_s}{R_1}(R1R2R3)Va=R1Vs
(b)(1R1+1R2+1R3)Va=VsR1\left(-\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\right)\times V_a =\frac{V_s}{R_1}(R11+R21+R31)Va=R1Vs
(c)(1R1+1R2+1R3)Va=VsR1\left(\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\right)\times V_a =\frac{V_s}{R_1}(R11+R21+R31)Va=R1Vs
(d)(R1+R2+R3)Va=VsR1(R_1+ R_2+ R_3)\times V_a =\frac{V_s}{R_1}(R1+R2+R3)Va=R1Vs
(e)(1R1+1R21R3)Va=VsR1\left(\frac{1}{R_1}+\frac{1}{R_2}-\frac{1}{R_3}\right)\times V_a =\frac{V_s}{R_1}(R11+R21R31)Va=R1Vs
Va=V_a =Va=________ VVV

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