Warren Bridge

${\displaystyle \underset{?}{\overset{?}{}}}Fx=0$

BAX $=0$

${\displaystyle \underset{?}{\overset{?}{}}}MA=0$

REY $(12)+67\mathrm{.}5(6)=0$

REY $=\frac{-67\mathrm{.}5(6)}{-12}$

REY $=33\mathrm{.}75$

${\displaystyle \underset{?}{\overset{?}{}}}ME=0$

RAY $=\frac{67\mathrm{.}5(6)}{12}$

RAY $=33\mathrm{.}75$

Check

$33\mathrm{.}75+33\mathrm{.}75-67\mathrm{.}5$

$=0$

I already have all the reactions of the warren bridge now i need all the forces of the trusses joints using the joints and section method combine.