Watching TV: The 2012 general Social Survey asked a large number of people how much time...

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Watching TV: The 2012 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hou was 3.09 with a standard deviation of 2.93. Assume that in a sample of 39 teenagers, the sample standard deviation of daily TV time is 4.5 hours, and that the population of TV watching times is normally distributed. Can you conclude that the population standard deviation of TV watching times for teenagers is greater than 2.93? Use the a 0.01 level of significance. Part 1 of 5 State the appropriate null and alternate hypotheses. H:o = H₁ :o > 2.93 2.93 This hypothesis test is a right-tailed test. Part: 1 / 5 Part 2 of 5 Find the critical value. Round the answer to three decimal places. For a = 0.01, the critical value is X Watching TV: The 2012 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hou was 3.09 with a standard deviation of 2.93. Assume that in a sample of 39 teenagers, the sample standard deviation of daily TV time is 4.5 hours, and that the population of TV watching times is normally distributed. Can you conclude that the population standard deviation of TV watching times for teenagers is greater than 2.93? Use the a 0.01 level of significance. Part 1 of 5 State the appropriate null and alternate hypotheses. H:o = H₁ :o > 2.93 2.93 This hypothesis test is a right-tailed test. Part: 1 / 5 Part 2 of 5 Find the critical value. Round the answer to three decimal places. For a = 0.01, the critical value is X