WATER ENGINEFRING CIVTL ENGINEERING QUESTION$4$II

The water depth ea the erest of a herivontal$-$crest Crump was neeasured as $1\mathrm{.}219$ m $.$ Upstrean of the Creap an average pool width of $15\mathrm{.}24$ m was measered, with its bottom $610$ mm below the crest of the Crump. By assuming the upstrean pool to be rectangular in shape and that free Dow conditioes existed, deternine the discharge over the Crump by the step$-$by$-$step method. Take the width of the Crump as $10$ m and do a minimein of $6$ iterations.

The following Bow conditions ever a crump wrir shoald be zotrd:

When Dow rate $(Q)$ incrrases, the downitream water level $($Gd$)$ will rise ip to the poiat where it lafoesces the reading of the opstreani water level $($i$).$ This counes sobmergence condition to exiat and a different formula sboeld then be applied

The equation for horizontal crest "Crumps" for free Aow conditions, becomes

$Q=CD(g)H(E{)}^{is}$

Because $CD=0\mathrm{.}6327.$ and $g=9\mathrm{.}81ms.$ Q cin bet said to be $Q=1\mathrm{.}982b(E{)}^{13}$

Where: $b=$ upstream width of channel

$H=$ is measured $(m)$ which is the widt of the "Crump"

E $-$ total energy height in meter tion the crost of the weir by adding VI$/$Rg

Q $=$ dischrge in $m^{\frac{1}{3}}.$

Step I: $V=\frac{Q}{A}$ where the area is where H is mensured.

Step $2$: Va $\frac{2}{2}g=\frac{0}{2}g=0$

Step $3$: $E=H+\frac{V^2}{2}Z$

Step $4$:

By iterating many times $Q$ will stay the same and can thea be taken as the final answer.