Question: We are given the following indefinite integral. ( 4 - 1 t 5 ) 2 ( 1 t 6 ) d t Integration. Let u

We are given the following indefinite integral.
(4-1t5)2(1t6)dt
Integration.
Let u=4-1t5.
Find du.
du=(,)dt
Find the indefinite integral and check the result by differentiation.
(4-1t5)2(1t6)dt
Step 1
We are given the following indefinite integral
(4-1t2)2(1t6)dt
The integrand is a product of two quantities, with one raised to a power. If the second quantity can be written as the derivative of the quantity raised to a power, then a substitution will allow us to use the General Power Rule for Integration
Let U=4-155
Find du.
?du=|) dt
We are given the following indefinite integral. (

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