Question: We are going to compute the total unique numbers ( that have only one encoding ) in IEEE half - precision format as follows.First, we

We are going to compute the total "unique" numbers (that have only one encoding) in IEEE half-precision format as follows.First, we defineA = the total number of unique numbers for +infinity and +NaN (with sign bit 0 and exponent=31)B = the total number of unique +v normal numbers (with sign bit 0)C = the total number of unique +v subnormal numbers, including +0(with sign bit 0 and exponent 0).D= the total number of unique half-precision numbers.Give the values of A,B, C, and D below.Hints: D =2*(A+B+C)-2 as (+0,-0) and (+NaN,-NaN) are two pairs of numbers that represent the same value.

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