Question: We can see using the number circles that the TC expressions of N1 = 10 and N2 = 12 are 0b01010 and 0b10100 , respectively,

We can see using the number circles that the TC expressions of N1 = 10 and N2 = 12 are 0b01010 and 0b10100 , respectively, for a 5-bit system.

1. Extend the the above TC expressions to a 8-bit system. (See Examples 2 and 3 of Sec 4.2.4.) Write your solutions clearly as B1,8 and B2,8, respectively.

2. Shift the above numbers to the right by 1 bit to obtain B1,8,1 and B2,8,1, respectively. (When you shift a signed number to the right, you need to repeat the sign bit on the left side of the number.) Write your solutions clearly.

3. Express B1,8,1 and B2,8,1 back to decimal, and denote them as N1,1 and N2,1, respectively. (You can use the number circle if you want.)

4. (Compare N1,1 and N2,1 with N1 and N2, respectively. No points for this part.)

We can see using the number circles that the TC expressions of

Prob 2. (18 points total, 3 points cach) We can see using the number circles that the TC expressions of N1 = 10 and N2 = -12 are Ob01010 and Ob10100 , respectively, for a 5-bit system. 1. Extend the the above TC expressions to a 8-bit system. (See Examples 2 and 3 of Sec 4.2.4.) Write your solutions clearly as B1,8 and B2,8, respectively. 2. Shift the above numbers to the right by 1 bit to obtain B1,8,1 and B2,8,1, respectively. (When you shift a signed number to the right, you need to repeat the sign bit on the left side of the number.) Write your solutions clearly. 3. Express B1,8,1 and B2,8,1 back to decimal, and denote them as N1,1 and N2,1, respectively. (You can use the number circle if you want.) 4. (Compare N1,1 and 12,1 with N and N2, respectively. No points for this part.)

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