Question: We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m=4. The plaintext given

We conduct a known-plaintext attack against an LFSR.

Through trial and error we have determined that the number of states is m=4.

The plaintext given by 00011111=x0x1x2x3x4x5x6x7 when encrypted by the LFSR produced the ciphertext 01110111=y0y1y2y3y3y5y6y7. What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent p3=0,p2=1,p1=0,p0=1).

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