Question: We define a real number to be algebraic if it is a solution of some polynomial equation Anx + an1x+...+ x + ao =

We define a real number to be algebraic if it is a

We define a real number to be algebraic if it is a solution of some polynomial equation Anx" + an1x+...+ x + ao = 0, where all the coefficients are integers. Thus 2 is algebraic because it is a solution of r - 2 = 0. The number is not algebraic because no such polynomial equation can ever be found (although this is hard to prove). Show that the set of algebraic numbers is countable. A real number that is not algebraic is said to be transcendental. For example, it is known that e and are transcendental. What can you say about the existence of other transcendental numbers?

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

Answer A 8 D 9 Explanation The detailed explanation f... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Accounting Questions!