We drilled a ${12\mathrm{.}25}^{\text{'}\text{'}}$ vertical hole section down to $10,000ft.$ The previous casing, $13-$

$\frac{3}{8^{\text{'}\text{'}}},72\frac{lbf}{ft},$ was run and cemented at $2,000ft.$ We will run and cement $9-\frac{5}{8^{\text{'}\text{'}}}$

casing $(47l\frac{b}{f}t).$ We want to perform a two$-$stage cement job. DV tool and float

collar will be set at $5,500ft$ and $9,920ft,$ respectively. In both stages, we would like

to have $600$ ft tail cement. Excess in the open hole section and Safety Factor $($SF$)$ for

thickening time are $100\%$ and $90$ minutes, respectively. The lead and tail cement data

for both stages are given in the following table. Calculate:

a$)$ Volume of both tail and lead cements required for both stages.

b$)$ Number of sacks of cement required for both tail and lead cement in each

stage.

c$)$ Displacement volume.

d$)$ If we do cement and displacement at $7$ and $8bb\frac{l}{m}in(bpm),$ respectively,

what would be the minimum thickening time for each slurry?

e$)$ Draw an idealized pressure vs$.$ volume chart for the job, if no loss happens.

You need to explain each part of the graph.

Note I: The weight of each sack of cement is $94$ lbs $.$

Note II: Ignore the rat hole volume.