We have found the partial derivatives of the Lagrangian function as listed below. Fx =38x + Fy =26y +6 F= x +6y 2 The candidates for the relative extrema of the function f(x, y)=3x +2y 4x23y2 are the solutions to the system of equations obtained when we set the partial derivatives equal to 0. Thus, we must solve the following system of equations. 38x +=026y +6=0 x +6y 2=0 First, solve the first and second equations for x and y in terms of . x =3+8 y =2+66 Now substitute these expressions into the third equation, and solve for .3+8+62+662=038+8+2+62=049/8== Substitute this value for into the above expressions for x and y, and then evaluate. (Round your answer to three decimal places.) x =0.367