We have learned that the preprocessor expands macros before compilation. Consider the following macro: #define SQUARE(x) (x * x) If we use the macro as follows: int x = 5; int x2; x2 = SQUARE(x+1); printf("x2: %d ", x2); What value is printed for x2? Question 9 options: 6, because the macro just adds x and 1 11, because the macro evaluates to x + 1 * x + 1 in the expansion. 36, because the macro includes parenthesis and is perfectly written -1, because the macro generates an error